Raul can do a piece of work in 20 days and Kate in 25 days. They work together for 5 days and then Kate leaves. In how many more days would Raul finish the work?
Raul can do a piece of work in 20 days So, this means Raul works at the rate of = 1 ÷ 20 = 0.05 per day (equivalent of 5% per day)
and Kate in 25 days and Kate works at the rate of = 1 ÷ 25 = 0.04 per day (equivalent of 4% per day)
They work together for 5 days and then Kate leaves The percentage of work completed in that 5 days is (5% * 5) + (4% * 5) = 45% (or 0.45)
Remaining work = 100% - 45% = 55%
So, Raul does 5% of work per day and has 55% of work to complete, that will take him: 55% ÷ 5% = 11 days to complete
Raul can do a piece of work in 20 days and Kate in 25 days. They work together for 5 days and then Kate leaves. In how many more days would Raul finish the work?
Raul can do a piece of work in 20 days So, this means Raul works at the rate of = 1 ÷ 20 = 0.05 per day (equivalent of 5% per day)
and Kate in 25 days and Kate works at the rate of = 1 ÷ 25 = 0.04 per day (equivalent of 4% per day)
They work together for 5 days and then Kate leaves The percentage of work completed in that 5 days is (5% * 5) + (4% * 5) = 45% (or 0.45)
Remaining work = 100% - 45% = 55%
So, Raul does 5% of work per day and has 55% of work to complete, that will take him: 55% ÷ 5% = 11 days to complete
Answer: 11 days
BY Riddles Repository - Answers
Warning: Undefined variable $i in /var/www/tg-me/post.php on line 283
